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Which of the folllowing shows geometrica...

Which of the folllowing shows geometrical isomerism ?

A

But-1-ene

B

But-2-ene

C

Prop-1-ene

D

Pent-1-ene

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The correct Answer is:
To determine which of the given compounds shows geometrical isomerism, we need to analyze the structures of each compound and identify if they have a double bond with two different groups attached to each carbon of the double bond. ### Step-by-Step Solution: 1. **Understanding Geometrical Isomerism**: Geometrical isomerism occurs in compounds with a double bond (C=C) where there are two different groups attached to each carbon of the double bond. The two forms are known as cis (same side) and trans (opposite sides). 2. **Analyzing the First Compound: But-1-ene**: - Structure: CH2=CH-CH2-CH3 - Groups attached to the double bond: CH2 and CH3 on one side, and H and H on the other. - Since both groups on one side are hydrogen atoms (H), this compound cannot exhibit geometrical isomerism. - **Conclusion**: But-1-ene does not show geometrical isomerism. 3. **Analyzing the Second Compound: But-2-ene**: - Structure: CH3-CH=CH-CH3 - Groups attached to the double bond: CH3 and H on one carbon, and CH3 and H on the other carbon. - Here, both carbons of the double bond have different groups (CH3 and H). - This allows for cis (both CH3 on the same side) and trans (CH3 on opposite sides) configurations. - **Conclusion**: But-2-ene shows geometrical isomerism. 4. **Analyzing the Third Compound: Prop-1-ene**: - Structure: CH2=CH-CH3 - Groups attached to the double bond: CH2 and H on one side, and CH3 on the other. - Since there are no two different groups on both sides of the double bond, this compound cannot exhibit geometrical isomerism. - **Conclusion**: Prop-1-ene does not show geometrical isomerism. 5. **Analyzing the Fourth Compound: Pent-1-ene**: - Structure: CH2=CH-CH2-CH2-CH3 - Groups attached to the double bond: CH2 and H on one side, and CH2-CH2-CH3 on the other. - Similar to the previous cases, there are no two different groups on both sides of the double bond. - **Conclusion**: Pent-1-ene does not show geometrical isomerism. ### Final Answer: The only compound that shows geometrical isomerism is **But-2-ene**.
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AAKASH INSTITUTE ENGLISH-HYDROCARBONS-Assignment(Section - A) (Obejctive type question)
  1. The reaction of CH(3)CH=CH(2) with HOCl will yield

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  2. C(6)H(5)CH(2)CH(2)CH(3) is when oxidised in the presence of alk. KMnO(...

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  3. Toulene overset(K(2)Cr(2)O(7))underset(H(2)SO(4))to Y. Here Y is

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  4. C(6)H(6)+Z overset(Anhy.AlCl(3))to Toluene The compound Z is

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  5. C(6)H(6) overset("Oxidation")underset(V(2)O(5)//Delta)to X. Here, X is

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  6. In kharash effect,reaction follows

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  7. A,B and C can be

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  8. Benzene undergoes substituion reaction more easily than addition becau...

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  9. A mixture of C(2)H(6), C(2)H(4) and C(2)H(2) is bubbled through alkali...

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  10. Ethylene reacts with S(2)Cl(2) to give

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  11. Ph-C-=CH overset(Hg^(+),H^(+)//H(2)O)to A Aditon of H(2)O in the rea...

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  12. Monomer of neoprene is

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  13. Compound A is :

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  14. Compound A is :

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  15. Which of the following is active species in sulphonation of benzene ?

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  16. Which one is o, p-directiong group for electrophliic substitution reac...

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  17. underset((I))("In Chlorobenzene") , underset((II))("2,4-dinitrochlorob...

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  18. CH(3)-CH=CH-CH(2)-CH(3) overset(HI)to underset("major")A Compound A ...

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  19. The electrophilie which attacks in Friedel-Craft acylation is

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  20. Which of the folllowing shows geometrical isomerism ?

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