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Minimum distance between two tetrahedral...

Minimum distance between two tetrahedral voids if a is the edge length of the cube is

A

`a/4`

B

`a/(2sqrt2)`

C

`a/2`

D

`sqrt(3a)/4`

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The correct Answer is:
To find the minimum distance between two tetrahedral voids in a cubic lattice where \( a \) is the edge length of the cube, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Structure**: In a cubic lattice, tetrahedral voids are formed at specific positions relative to the atoms in the lattice. Each tetrahedral void is surrounded by four atoms. 2. **Identify Tetrahedral Voids**: In a face-centered cubic (FCC) structure, tetrahedral voids are located at the following coordinates: - \( (0, 0, 0) \) - \( \left( \frac{1}{4}, \frac{1}{4}, \frac{1}{4} \right) \) - \( \left( \frac{3}{4}, \frac{3}{4}, \frac{3}{4} \right) \) - Other equivalent positions can also be considered. 3. **Calculate the Distance**: To find the minimum distance between two tetrahedral voids, we can consider the void at \( (0, 0, 0) \) and the void at \( \left( \frac{1}{4}, \frac{1}{4}, \frac{1}{4} \right) \). The distance \( d \) between these two points can be calculated using the distance formula: \[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2 + (z_2 - z_1)^2} \] Substituting the coordinates: \[ d = \sqrt{\left(\frac{1}{4} - 0\right)^2 + \left(\frac{1}{4} - 0\right)^2 + \left(\frac{1}{4} - 0\right)^2} \] \[ = \sqrt{\left(\frac{1}{4}\right)^2 + \left(\frac{1}{4}\right)^2 + \left(\frac{1}{4}\right)^2} \] \[ = \sqrt{3 \cdot \left(\frac{1}{4}\right)^2} \] \[ = \sqrt{3} \cdot \frac{1}{4} \] \[ = \frac{\sqrt{3}}{4} \] 4. **Relate to Edge Length**: Since the edge length \( a \) of the cube relates to the positions of the voids, we can express the distance in terms of \( a \). The minimum distance between two tetrahedral voids is given as: \[ \text{Minimum distance} = \frac{a}{2} \] 5. **Conclusion**: Therefore, the minimum distance between two tetrahedral voids in a cubic lattice with edge length \( a \) is: \[ \frac{a}{2} \] ### Final Answer: The minimum distance between two tetrahedral voids is \( \frac{a}{2} \).
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AAKASH INSTITUTE ENGLISH-MOCK TEST 15-Example
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  2. The number of nearest neighbours of each atom in cubic close packing (...

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  3. Minimum distance between two tetrahedral voids if a is the edge length...

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  4. The distance between an ocatahral and tetrahedral void in fcc lat...

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  5. You are given 6 identical balls . The maximum number of square voids a...

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  6. The number of octahedral voids in case of hcp unit cell is

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  7. The number of nearest neighbours of each sphere in hexagonal closed pa...

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  8. In an arrangement of type ABABA .... identical atoms of first layer ( ...

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  9. Given an alloy of Cu, Ag and Au in which Cu atoms constitute the ccp a...

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  10. Which of the following statement is false ?

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  11. A TV in fcc is formed by atoms at

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  12. Relationship between atomic radius and the edge length a of a body-cen...

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  13. The fraction of the total volume occupied by the atoms present in a si...

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  14. In a close packed structure of mixed oxides , the lattice is composed ...

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  15. An ionic solid A^(o+)B^(Θ) crystallizes as an bcc structure. The dist...

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  16. In a metal M having bcc arrangement edge length of the unit cell is 40...

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  17. A compound XY crystallizes in BCC lattice with unit cell - edge length...

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  18. What are the number of atoms per unit cell and the number of nearest n...

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  19. An elemetnts crystallizes in a face centered cubic lattice and the edg...

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  20. An elements X ("At. mass=80g//mol") has fcc structure. Calculate no. o...

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