A cricket ball of mass 100 g moving with a speed of `30 "ms"^(-1)` is brought to rest by a player in 0.03 s. Find the change in momentum of ball.

Explanation

Given, m = 100 g `=(100)/(1000) kg = 0.1 kg, u = 30 ms^(-1)`
v= 0 , t = 0.03 s.
Initial momentum = mu
`= 0.1xx30=3.0 kg m s^(-1)`
final momentum = mv
`=0.1xx0=0`
change in momentum = final momentum - Initial momentum
`=0-3.0 =- 3.0 kg m s^(-1)`