Taking the mass of earth equal to `6 xx 10^(24)` kg and its radius equal to `6.4 xx 10^6` m, calculate the value of acceleration due to gravity at a height of 2000 km above the earth surface. Take G = `6.7xx10^(-11) N m^(2) kg^(-2)`

Explanation

To calculate the acceleration due to gravity at a height of 2000 km above the Earth's surface, we can follow these steps:

### Step 1: Write down the given data
- Mass of the Earth (M) = \(6 \times 10^{24}\) kg
- Radius of the Earth (R) = \(6.4 \times 10^{6}\) m
- Height above the Earth's surface (h) = 2000 km = \(2000 \times 10^{3}\) m = \(2 \times 10^{6}\) m
- Gravitational constant (G) = \(6.7 \times 10^{-11} \, \text{N m}^2 \text{kg}^{-2}\)

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