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A stone at rest is dropped from a height...

A stone at rest is dropped from a height and falls freely under gravity. Calculate the distance covered by it in the first two seconds. (g = 9.8 m`s^(-2)`)

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To solve the problem of calculating the distance covered by a stone dropped from rest in the first two seconds, we can use the second equation of motion. Here’s the step-by-step solution: ### Step 1: Identify the known values - Initial velocity (u) = 0 m/s (since the stone is at rest) - Time (t) = 2 seconds - Acceleration due to gravity (g) = 9.8 m/s² ### Step 2: Write the second equation of motion ...
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