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A body is dropped freely under gravity f...

A body is dropped freely under gravity from the top of a tower of height 78.4 m. Calculate : (i) the time to reach the ground .
Take g = 9.8 m`s^(-2)`.

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To solve the problem of a body dropped freely from a height of 78.4 m under the influence of gravity, we can use the second equation of motion. Here’s the step-by-step solution: ### Step 1: Identify the known values - Initial velocity (u) = 0 m/s (since the body is dropped) - Height of the tower (h) = 78.4 m - Acceleration due to gravity (g) = 9.8 m/s² ### Step 2: Write the second equation of motion ...
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Knowledge Check

  • A body is released form the top of a tower of height h meters. It takes t seconds to reach the ground. Where is the ball at the time t/2 sec ?

    A
    at h/2 meter from the ground
    B
    at h/4 meter from the ground
    C
    depends upon the mass and volume of the ball
    D
    at 3h/4 meter from the ground.
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