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A body is dropped freely under gravity f...

A body is dropped freely under gravity from the top of a tower of height 78.4 m. Calculate : (i) the time to reach the ground .
Take g = 9.8 m`s^(-2)`.

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To solve the problem of a body dropped freely from a height of 78.4 m under the influence of gravity, we can use the second equation of motion. Here’s the step-by-step solution: ### Step 1: Identify the known values - Initial velocity (u) = 0 m/s (since the body is dropped) - Height of the tower (h) = 78.4 m - Acceleration due to gravity (g) = 9.8 m/s² ### Step 2: Write the second equation of motion ...
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ICSE-LAWS OF MOTION-EXAMPLES
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  2. A ball of mass 10 g is moving with a velocity of 50 "ms"^(-1). On appl...

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  9. A body of mass 10 kg is taken from the earth to the moon. If the value...

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  17. A ball is thrown vertically upwards. It goes to a height 19.6 m and th...

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