A body is dropped freely under gravity from the top of a tower of height 78.4 m. Calculate : the velocity with which it strikes the ground.
Take g = 9.8 m`s^(-2)`.

Explanation

To solve the problem of a body dropped freely from a height of 78.4 m, we will use the third equation of motion. Here are the steps to find the final velocity with which the body strikes the ground:

### Step-by-Step Solution:

1. **Identify the Given Values:**
- Height (h) = 78.4 m
- Acceleration due to gravity (g) = 9.8 m/s²
- Initial velocity (u) = 0 m/s (since the body is dropped from rest)
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