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The area of a rectangle increases by 200...

The area of a rectangle increases by 200 sq, m, if the length is increased by 8 m and the breadth by 3 m. The area increases by 255 sq. m, if the length is increased by 3 m and breadth by 8m. Find the length and the breadth of the rectangle.

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To solve the problem, we need to set up equations based on the information provided about the rectangle's area changes. Let's denote the length of the rectangle as \( L \) meters and the breadth as \( B \) meters. ### Step 1: Set Up the Equations 1. The area of the rectangle is given by \( A = L \times B \). 2. When the length is increased by 8 meters and the breadth by 3 meters, the new area becomes: \[ (L + 8)(B + 3) = LB + 200 \] Expanding this gives: \[ LB + 3L + 8B + 24 = LB + 200 \] Simplifying, we get: \[ 3L + 8B + 24 = 200 \] Thus, the first equation is: \[ 3L + 8B = 176 \quad \text{(Equation 1)} \] 3. When the length is increased by 3 meters and the breadth by 8 meters, the new area becomes: \[ (L + 3)(B + 8) = LB + 255 \] Expanding this gives: \[ LB + 8L + 3B + 24 = LB + 255 \] Simplifying, we get: \[ 8L + 3B + 24 = 255 \] Thus, the second equation is: \[ 8L + 3B = 231 \quad \text{(Equation 2)} \] ### Step 2: Solve the System of Equations Now we have a system of two equations: 1. \( 3L + 8B = 176 \) (Equation 1) 2. \( 8L + 3B = 231 \) (Equation 2) We can solve these equations using the elimination or substitution method. Here, we will use the elimination method. ### Step 3: Multiply and Eliminate To eliminate \( B \), we can multiply Equation 1 by 3 and Equation 2 by 8: - From Equation 1: \[ 9L + 24B = 528 \quad \text{(Equation 3)} \] - From Equation 2: \[ 64L + 24B = 1848 \quad \text{(Equation 4)} \] Now, we can subtract Equation 3 from Equation 4: \[ (64L + 24B) - (9L + 24B) = 1848 - 528 \] This simplifies to: \[ 55L = 1320 \] Thus, we find: \[ L = \frac{1320}{55} = 24 \quad \text{(Length)} \] ### Step 4: Substitute to Find Breadth Now that we have \( L = 24 \), we can substitute this value back into either Equation 1 or Equation 2 to find \( B \). We'll use Equation 1: \[ 3(24) + 8B = 176 \] This simplifies to: \[ 72 + 8B = 176 \] Subtracting 72 from both sides gives: \[ 8B = 104 \] Thus, we find: \[ B = \frac{104}{8} = 13 \quad \text{(Breadth)} \] ### Final Answer The length of the rectangle is \( 24 \) meters and the breadth is \( 13 \) meters.
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