Home
Class 9
MATHS
A and B have 460 coins altogether. If (...

A and B have 460 coins altogether. If ` (3)/(4)` of A's number of coins is equal to ` ( 2)/(5)` of B's number of coins, find how many coins must B give to A so that they both have equal number of coins.

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step-by-step, we will follow the information given and use algebra to find the number of coins A and B have, and then determine how many coins B must give to A for them to have an equal number of coins. ### Step 1: Set up the equations Let A be the number of coins A has, and B be the number of coins B has. According to the problem, we have: 1. \( A + B = 460 \) (Equation 1) 2. \( \frac{3}{4}A = \frac{2}{5}B \) (Equation 2) ### Step 2: Rearranging Equation 2 From Equation 2, we can express A in terms of B: \[ \frac{3}{4}A = \frac{2}{5}B \] Multiplying both sides by 20 (the least common multiple of 4 and 5) to eliminate the fractions: \[ 20 \cdot \frac{3}{4}A = 20 \cdot \frac{2}{5}B \] This simplifies to: \[ 15A = 8B \] Now, we can express A in terms of B: \[ A = \frac{8}{15}B \quad \text{(Equation 3)} \] ### Step 3: Substitute A in Equation 1 Now, substitute Equation 3 into Equation 1: \[ \frac{8}{15}B + B = 460 \] To combine the terms, convert B to a fraction: \[ \frac{8}{15}B + \frac{15}{15}B = 460 \] This simplifies to: \[ \frac{23}{15}B = 460 \] ### Step 4: Solve for B To find B, multiply both sides by the reciprocal of \(\frac{23}{15}\): \[ B = 460 \cdot \frac{15}{23} \] Calculating this gives: \[ B = 300 \] ### Step 5: Find A Now that we have B, we can find A using Equation 1: \[ A + 300 = 460 \] Thus: \[ A = 460 - 300 = 160 \] ### Step 6: Determine how many coins B must give to A Now, we need to find how many coins B must give to A so that they both have an equal number of coins. Let \( x \) be the number of coins B gives to A. After the transaction: - A will have \( 160 + x \) - B will have \( 300 - x \) We want these two amounts to be equal: \[ 160 + x = 300 - x \] Solving for \( x \): \[ 160 + x + x = 300 \] \[ 2x = 300 - 160 \] \[ 2x = 140 \] \[ x = 70 \] ### Final Answer B must give 70 coins to A. ---
Promotional Banner

Topper's Solved these Questions

  • CHAPTERWISE REVISION (STAGE 3)

    ICSE|Exercise INDICES |6 Videos
  • CHAPTERWISE REVISION (STAGE 3)

    ICSE|Exercise LOGARITHM |9 Videos
  • CHAPTERWISE REVISION (STAGE 3)

    ICSE|Exercise FACTORS |9 Videos
  • CHAPTERWISE REVISION (STAGE 1)

    ICSE|Exercise Graphical solution |10 Videos
  • CIRCLE

    ICSE|Exercise EXERCISE 17(D)|12 Videos

Similar Questions

Explore conceptually related problems

A and B toss 3 coins . The probability that they both obtain the same number of heads is

A coin is tossed 3 times by 2 persons. The prbability that both get equal number of heads, is

Each of A and B tosses two coins. What is the probability that they get equal number of heads ?

The least number of times a fair coin must be tossed so that the probability of getting atleast one head is atleast 0.8 is

I have a total of Rs 300 in coins of denomination Re 1, Rs 2 and Rs 5. The number of Rs 2 coins is 3 times the number of Rs 5 coins. The total number of coins is 160. How many coins of each denomination are with me?

Saurabh has Rs 34 fifty paise and twenty-five paise coins. If the number of 25 paise coins be twice the number of 50 paise coins, how many coins of each type does he have:?

Find the number of possible outcomes of tossing a coin twice.

Find the expectation of the number of heads in 15 tosses of a coin.

There are some 50 paisa and some 25 paisa coins in a ba. If the total number of coins is 30 and their total value is Rs. 11, find the number of coins of each kind.

Mr. Mohan has 256rs in the form of 1rs and 2rs coins. If the number of 2rs coins are three more than twice the number of 1rs coins find the total value of 2rs coins