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In the given figure, if DE || BC, AE = 8...

In the given figure, if DE || BC, AE = 8 cm, EC = 2 cm and BC = 6 cm, then find DE

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To solve the problem, we will use the properties of similar triangles. Here’s a step-by-step solution: ### Step 1: Identify the triangles We have two triangles, triangle ADE and triangle ABC. Since DE is parallel to BC, we can use the properties of similar triangles. ### Step 2: Establish similarity Since DE || BC, we know that: - Angle DAE = Angle BAC (common angle) - Angle ADE = Angle ABC (corresponding angles) Thus, by the Angle-Angle (AA) criterion for similarity, triangle ADE is similar to triangle ABC. ### Step 3: Set up the proportion For similar triangles, the ratios of corresponding sides are equal. Therefore, we can write the following proportion: \[ \frac{AE}{EC} = \frac{DE}{BC} \] ### Step 4: Substitute known values We know: - AE = 8 cm - EC = 2 cm - BC = 6 cm Substituting these values into the proportion gives us: \[ \frac{8}{2} = \frac{DE}{6} \] ### Step 5: Simplify the left side Calculating the left side: \[ \frac{8}{2} = 4 \] So, we have: \[ 4 = \frac{DE}{6} \] ### Step 6: Cross-multiply to solve for DE Cross-multiplying gives us: \[ 4 \times 6 = DE \] \[ DE = 24 \] ### Step 7: Solve for DE Now, we need to find DE in terms of the total length AE + EC: \[ AE + EC = 8 + 2 = 10 \] Now we can set up the proportion again: \[ \frac{DE}{BC} = \frac{DE}{6} = \frac{8}{10} \] ### Step 8: Solve for DE Cross-multiplying gives us: \[ 10 \cdot DE = 48 \] \[ DE = \frac{48}{10} = 4.8 \text{ cm} \] ### Final Answer Thus, the length of DE is: \[ DE = 4.8 \text{ cm} \] ---
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ICSE-MEASURES OF CENTRAL TENDENCY (MEAN, MEDIAN, QUARTILES AND MODE)-EXERCISE 24 (E)
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