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Multiply : 2a^(2) - 5a - 4 and -3a...

Multiply :
`2a^(2) - 5a - 4` and `-3a`

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To solve the problem of multiplying the expression \(2a^2 - 5a - 4\) by \(-3a\), we will follow these steps: ### Step 1: Distribute \(-3a\) to each term in the polynomial \(2a^2 - 5a - 4\). We will multiply \(-3a\) with each term of the polynomial: 1. Multiply \(-3a\) by \(2a^2\): \[ -3a \cdot 2a^2 = -6a^3 \] 2. Multiply \(-3a\) by \(-5a\): \[ -3a \cdot (-5a) = 15a^2 \] 3. Multiply \(-3a\) by \(-4\): \[ -3a \cdot (-4) = 12a \] ### Step 2: Combine the results from the multiplications. Now, we will combine all the results we obtained from the multiplications: \[ -6a^3 + 15a^2 + 12a \] ### Final Answer: The final result of multiplying \(2a^2 - 5a - 4\) by \(-3a\) is: \[ -6a^3 + 15a^2 + 12a \] ---
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