If x = 2 and y = 1,
Find the value of `(-4x^(2)y^(3)) xx (-5x^(2)y^(5))`.

Answer

To find the value of the expression \((-4x^{2}y^{3}) \times (-5x^{2}y^{5})\) when \(x = 2\) and \(y = 1\), we will follow these steps:

### Step 1: Substitute the values of \(x\) and \(y\) into the expression.
We start with the expression:
\[ (-4x^{2}y^{3}) \times (-5x^{2}y^{5}) \]
Substituting \(x = 2\) and \(y = 1\):
\[ (-4(2)^{2}(1)^{3}) \times (-5(2)^{2}(1)^{5}) \]

### Step 2: Calculate the powers of \(x\) and \(y\).
Calculating \(2^{2}\) and \(1^{3}\) and \(1^{5}\):
\[ = (-4 \cdot 4 \cdot 1) \times (-5 \cdot 4 \cdot 1) \]
Where \(2^{2} = 4\) and \(1^{3} = 1\), \(1^{5} = 1\).

### Step 3: Simplify the expression.
Now, we can simplify the expression:
\[ = (-4 \cdot 4) \times (-5 \cdot 4) \]
Calculating each part:
\[ = (-16) \times (-20) \]

### Step 4: Multiply the results.
Now, we multiply \(-16\) and \(-20\):
\[ = 16 \times 20 \]
Calculating \(16 \times 20\):
\[ = 320 \]

### Final Answer:
Thus, the value of the expression is:
\[ \boxed{320} \]

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