Let `R_(1)= {(x,y)in RxxR :x = lambda y implies lambda in Q}` is a relation, R is set of real numbers then `R_(1)` is

Options

A. equivalence
B. only symmetric
C. not symmetric
D. not reflexive

Answer

C

Explanation

Let `R_(1) = {(x,y)in RxxR : x = lambda y}` ……….
`x = lambda x implies lambda = 1 epsilon Q` reflexive `(x)/(y)= lambda` is rotional
`implies (y)/(x) = (1)/(lambdas)` may or may not be rational for example `lambda = 0`
`epsilon Q`
But `(1)/(lambda) = (1)/(0)cancelepsilon Q` so not symmetric