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If x in(1, 30) and (1+tan x^(@))(1+tan(x...

If `x in(1, 30)` and `(1+tan x^(@))(1+tan(x+1)^(@))...(1+tan(x+44)^(@)) = 2^(23)` then value of x is

A

`0`

B

`1`

C

`2`

D

`3`

Text Solution

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The correct Answer is:
To solve the problem, we need to evaluate the expression given in the question step by step. ### Step-by-Step Solution: 1. **Understanding the Expression**: We need to evaluate the expression: \[ (1 + \tan x^\circ)(1 + \tan(x + 1)^\circ)(1 + \tan(x + 2)^\circ) \ldots (1 + \tan(x + 44)^\circ) = 2^{23} \] 2. **Setting Up the Function**: Let's define: \[ f(x) = (1 + \tan x^\circ)(1 + \tan(x + 1)^\circ)(1 + \tan(x + 2)^\circ) \ldots (1 + \tan(x + 44)^\circ) \] 3. **Substituting Values**: We will first evaluate \( f(1) \): \[ f(1) = (1 + \tan 1^\circ)(1 + \tan 2^\circ)(1 + \tan 3^\circ) \ldots (1 + \tan 45^\circ) \] 4. **Using the Identity**: Notice that: \[ \tan(45^\circ - a) = \frac{1 - \tan a}{1 + \tan a} \] This means: \[ 1 + \tan(45^\circ - a) = \frac{2}{1 + \tan a} \] Therefore, we can pair terms: \[ (1 + \tan 1^\circ)(1 + \tan 44^\circ), (1 + \tan 2^\circ)(1 + \tan 43^\circ), \ldots, (1 + \tan 22^\circ)(1 + \tan 23^\circ) \] 5. **Calculating the Pairs**: Each pair can be simplified: \[ (1 + \tan a)(1 + \tan(45^\circ - a)) = (1 + \tan a)\left( \frac{2}{1 + \tan a} \right) = 2 \] There are 22 such pairs, and one additional term \( (1 + \tan 45^\circ) = 2 \). 6. **Final Calculation**: Thus, we have: \[ f(1) = 2^{22} \cdot 2 = 2^{23} \] 7. **Conclusion**: Since \( f(1) = 2^{23} \), we conclude that the value of \( x \) that satisfies the equation is: \[ x = 1 \] ### Final Answer: The value of \( x \) is \( \boxed{1} \).

To solve the problem, we need to evaluate the expression given in the question step by step. ### Step-by-Step Solution: 1. **Understanding the Expression**: We need to evaluate the expression: \[ (1 + \tan x^\circ)(1 + \tan(x + 1)^\circ)(1 + \tan(x + 2)^\circ) \ldots (1 + \tan(x + 44)^\circ) = 2^{23} ...
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