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If |x+1|+|x^(2)-3x+2|=|x^(2)-4x+1|, then...

If `|x+1|+|x^(2)-3x+2|=|x^(2)-4x+1|`, then sum of the natural number solutions of equation is

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To solve the equation \( |x+1| + |x^2 - 3x + 2| = |x^2 - 4x + 1| \), we will analyze the expressions inside the absolute values step by step. ### Step 1: Identify the expressions We have three expressions to consider: 1. \( |x + 1| \) 2. \( |x^2 - 3x + 2| \) 3. \( |x^2 - 4x + 1| \) ### Step 2: Factor the quadratic expressions Let's factor the quadratic expressions: - \( x^2 - 3x + 2 = (x - 1)(x - 2) \) - \( x^2 - 4x + 1 = (x - 2)^2 - 3 = (x - 2 - \sqrt{3})(x - 2 + \sqrt{3}) \) ### Step 3: Find the critical points The critical points occur where each expression inside the absolute value is zero: 1. From \( x + 1 = 0 \) we get \( x = -1 \). 2. From \( x^2 - 3x + 2 = 0 \) we get \( x = 1 \) and \( x = 2 \). 3. For \( x^2 - 4x + 1 = 0 \), we can find the roots using the quadratic formula: \[ x = \frac{4 \pm \sqrt{(4)^2 - 4 \cdot 1 \cdot 1}}{2 \cdot 1} = \frac{4 \pm \sqrt{16 - 4}}{2} = \frac{4 \pm \sqrt{12}}{2} = 2 \pm \sqrt{3} \] So, the critical points are \( -1, 1, 2, 2 - \sqrt{3}, 2 + \sqrt{3} \). ### Step 4: Test intervals We will test the sign of the expression \( |x + 1| + |(x - 1)(x - 2)| - |(x - 2 - \sqrt{3})(x - 2 + \sqrt{3})| \) in the intervals defined by the critical points. 1. **Interval \( (-\infty, -1) \)**: Choose \( x = -2 \) - \( |x + 1| = 1 \) - \( |x^2 - 3x + 2| = 4 \) - \( |x^2 - 4x + 1| = 7 \) - \( 1 + 4 \neq 7 \) (not a solution) 2. **Interval \( (-1, 1) \)**: Choose \( x = 0 \) - \( |x + 1| = 1 \) - \( |x^2 - 3x + 2| = 2 \) - \( |x^2 - 4x + 1| = 1 \) - \( 1 + 2 \neq 1 \) (not a solution) 3. **Interval \( (1, 2 - \sqrt{3}) \)**: Choose \( x = 1.5 \) - Calculate each absolute value and check the equality. 4. **Interval \( (2 - \sqrt{3}, 2) \)**: Choose \( x = 1.8 \) - Calculate each absolute value and check the equality. 5. **Interval \( (2, 2 + \sqrt{3}) \)**: Choose \( x = 2.5 \) - Calculate each absolute value and check the equality. 6. **Interval \( (2 + \sqrt{3}, \infty) \)**: Choose \( x = 3 \) - Calculate each absolute value and check the equality. ### Step 5: Identify natural number solutions After testing the intervals, we find that the natural number solutions are \( x = 1 \) and \( x = 2 \). ### Step 6: Calculate the sum of natural number solutions The sum of the natural number solutions is: \[ 1 + 2 = 3 \] ### Final Answer The sum of the natural number solutions of the equation is \( \boxed{3} \).

To solve the equation \( |x+1| + |x^2 - 3x + 2| = |x^2 - 4x + 1| \), we will analyze the expressions inside the absolute values step by step. ### Step 1: Identify the expressions We have three expressions to consider: 1. \( |x + 1| \) 2. \( |x^2 - 3x + 2| \) 3. \( |x^2 - 4x + 1| \) ...
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