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The solution set of inequation |x^(2)-2x...

The solution set of inequation `|x^(2)-2x|+|x-4|gt|x^(2)-3x+4|` is a subset of

A

`(0, oo)`

B

`(0, 4)`

C

`(0, 2)`

D

`(4, oo)`

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To solve the inequality \( |x^2 - 2x| + |x - 4| > |x^2 - 3x + 4| \), we will break it down step by step. ### Step 1: Analyze the absolute value expressions We need to identify the points where the expressions inside the absolute values change their signs. 1. \( x^2 - 2x = 0 \) gives \( x(x - 2) = 0 \) → roots at \( x = 0 \) and \( x = 2 \). 2. \( x - 4 = 0 \) gives \( x = 4 \). 3. \( x^2 - 3x + 4 = 0 \) does not have real roots (discriminant \( = (-3)^2 - 4 \cdot 1 \cdot 4 < 0 \)). Thus, the critical points are \( x = 0, 2, 4 \). ### Step 2: Test intervals We will test the intervals determined by these critical points: \( (-\infty, 0) \), \( (0, 2) \), \( (2, 4) \), and \( (4, \infty) \). #### Interval 1: \( (-\infty, 0) \) - Here, \( x^2 - 2x \geq 0 \), \( x - 4 < 0 \), and \( x^2 - 3x + 4 > 0 \). - The inequality becomes: \[ (x^2 - 2x) - (4 - x) > (x^2 - 3x + 4) \] Simplifying gives: \[ x^2 - 2x - 4 + x > x^2 - 3x + 4 \] \[ 2x - 8 > 0 \implies x > 4 \] This is not possible in this interval. #### Interval 2: \( (0, 2) \) - Here, \( x^2 - 2x < 0 \), \( x - 4 < 0 \), and \( x^2 - 3x + 4 > 0 \). - The inequality becomes: \[ -(x^2 - 2x) - (4 - x) > (x^2 - 3x + 4) \] Simplifying gives: \[ -x^2 + 2x - 4 + x > x^2 - 3x + 4 \] \[ -2x^2 + 6x - 8 > 0 \implies x^2 - 3x + 4 < 0 \] This is not possible in this interval. #### Interval 3: \( (2, 4) \) - Here, \( x^2 - 2x > 0 \), \( x - 4 < 0 \), and \( x^2 - 3x + 4 > 0 \). - The inequality becomes: \[ (x^2 - 2x) - (4 - x) > (x^2 - 3x + 4) \] Simplifying gives: \[ x^2 - 2x - 4 + x > x^2 - 3x + 4 \] \[ 2x - 8 > 0 \implies x > 4 \] This is not possible in this interval. #### Interval 4: \( (4, \infty) \) - Here, \( x^2 - 2x > 0 \), \( x - 4 > 0 \), and \( x^2 - 3x + 4 > 0 \). - The inequality becomes: \[ (x^2 - 2x) + (x - 4) > (x^2 - 3x + 4) \] Simplifying gives: \[ x^2 - 2x + x - 4 > x^2 - 3x + 4 \] \[ 2x - 8 > 0 \implies x > 4 \] This is valid in this interval. ### Conclusion The solution set of the inequality is \( (4, \infty) \). ### Final Answer The solution set of the inequality is a subset of \( (4, \infty) \).

To solve the inequality \( |x^2 - 2x| + |x - 4| > |x^2 - 3x + 4| \), we will break it down step by step. ### Step 1: Analyze the absolute value expressions We need to identify the points where the expressions inside the absolute values change their signs. 1. \( x^2 - 2x = 0 \) gives \( x(x - 2) = 0 \) → roots at \( x = 0 \) and \( x = 2 \). 2. \( x - 4 = 0 \) gives \( x = 4 \). 3. \( x^2 - 3x + 4 = 0 \) does not have real roots (discriminant \( = (-3)^2 - 4 \cdot 1 \cdot 4 < 0 \)). ...
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