Home
Class 12
MATHS
The correct graph of y = (|log(2)x|)/(lo...

The correct graph of `y = (|log_(2)x|)/(log_(2)x)` is

A

B

C

D

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of graphing the function \( y = \frac{|\log_2 x|}{\log_2 x} \), we will analyze the function step by step. ### Step 1: Understanding the Function The function is defined as: \[ y = \frac{|\log_2 x|}{\log_2 x} \] ### Step 2: Determine the Domain The logarithm function \( \log_2 x \) is defined for \( x > 0 \). Therefore, the domain of the function is \( x > 0 \). ### Step 3: Analyze the Sign of \( \log_2 x \) 1. **For \( x > 1 \)**: - \( \log_2 x > 0 \) - Thus, \( |\log_2 x| = \log_2 x \) - Therefore: \[ y = \frac{\log_2 x}{\log_2 x} = 1 \] 2. **For \( 0 < x < 1 \)**: - \( \log_2 x < 0 \) - Thus, \( |\log_2 x| = -\log_2 x \) - Therefore: \[ y = \frac{-\log_2 x}{\log_2 x} = -1 \] ### Step 4: Summary of Values - For \( x > 1 \), \( y = 1 \) - For \( 0 < x < 1 \), \( y = -1 \) ### Step 5: Graph the Function - The graph will have a horizontal line at \( y = 1 \) for \( x > 1 \). - The graph will have a horizontal line at \( y = -1 \) for \( 0 < x < 1 \). - At \( x = 1 \), \( \log_2 1 = 0 \) is not defined in the function, so there is a discontinuity at this point. ### Step 6: Final Graph The graph consists of two horizontal lines: - A line at \( y = 1 \) for \( x > 1 \) - A line at \( y = -1 \) for \( 0 < x < 1 \) - There is a discontinuity at \( x = 1 \). ### Conclusion The correct graph of \( y = \frac{|\log_2 x|}{\log_2 x} \) is a piecewise function that takes the value of 1 for \( x > 1 \) and -1 for \( 0 < x < 1 \). ---

To solve the problem of graphing the function \( y = \frac{|\log_2 x|}{\log_2 x} \), we will analyze the function step by step. ### Step 1: Understanding the Function The function is defined as: \[ y = \frac{|\log_2 x|}{\log_2 x} \] ### Step 2: Determine the Domain The logarithm function \( \log_2 x \) is defined for \( x > 0 \). Therefore, the domain of the function is \( x > 0 \). ...
Promotional Banner

Topper's Solved these Questions

  • TEST PAPERS

    RESONANCE ENGLISH|Exercise PART : 1MATHEMATICS SEC - 1|1 Videos
  • TEST PAPERS

    RESONANCE ENGLISH|Exercise PART : 1MATHEMATICS|9 Videos
  • TEST PAPER

    RESONANCE ENGLISH|Exercise MATHEMATICS|48 Videos
  • TEST SERIES

    RESONANCE ENGLISH|Exercise MATHEMATICS|132 Videos

Similar Questions

Explore conceptually related problems

The correct graph of y = (|log_(2)2x|)/(log_(2)2x) is

Draw the graph of y=(log_(e)x)^(2)

Draw the graph of y=log_(2)x .

Sketch the graphs. y=log_(2)x

Draw the graph of y=1/(log_(e)x)

Draw the graph of y=-log_(e)x .

Draw the graph of y=|log_(e)|x|| .

Draw the graph of y= log_(x)sqrtx

Draw the graph of y= x ^((1)/(log_(e)x)) .

Sketch the graph of y=log_(0.5)|x|.

RESONANCE ENGLISH-TEST PAPERS-MATHEMATICS
  1. The correct graph of y = (|log(2)x|)/(log(2)x) is

    Text Solution

    |

  2. The least positive vlaue of the parameter 'a' for which there exist at...

    Text Solution

    |

  3. The locus of the midpoint of a chord of the circle x^2+y^2=4 which sub...

    Text Solution

    |

  4. If f(x)=x + tan x and f si the inverse of g, then g'(x) equals

    Text Solution

    |

  5. Tangents PA and PB are drawn to parabola y^(2)=4x from any arbitrary p...

    Text Solution

    |

  6. If lim(nrarroo) (n.2^(n))/(n(3x-4)^(n)+n.2^(n+1)+2^(n))=1/2 where "n" ...

    Text Solution

    |

  7. Eccentricity of ellipse 2(x-y+1)^(2)+3(x+y+2)^(2)=5 is

    Text Solution

    |

  8. If (tan^(-1)x)^(3)+(tan^(-1)y)^(3)=1-3tan^(-1)x.tan^(-1)y. Then which ...

    Text Solution

    |

  9. If f:RrarrR is a continuous function satisfying f(0)=1 and f(2x)-f(x)=...

    Text Solution

    |

  10. tan^(-1)(sinx)=sin^(-1)(tanx) holds true for

    Text Solution

    |

  11. The function f(x) = (x^(2) - 1)|x^(2) - 3x + 3|+cos (|x|) is not diffe...

    Text Solution

    |

  12. Consider parabola P(1)-=y=x^(2) and P(2)-=y^(2)=-8x and the line L-=lx...

    Text Solution

    |

  13. If the normals at (x(i),y(i)) i=1,2,3,4 to the rectangular hyperbola x...

    Text Solution

    |

  14. Let f(x) = x^(3) - x^(2) + x + 1 and g(x) = {{:(max f(t)",", 0 le t le...

    Text Solution

    |

  15. The sum of the roots of the equation tan^(-1)(x+3)-tan^(-1)(x-3)="sin"...

    Text Solution

    |

  16. For an ellipse having major and minor axis along x and y axes respecti...

    Text Solution

    |

  17. If f:[0,1]rarrR is defined as f(x)={(x^(3)(1-x)"sin"1/(x^(2)) 0ltxle1)...

    Text Solution

    |

  18. If f(x)=root (3)(8x^(3)+mx^(2))-nx such that lim(xrarroo)f(x)=1 then

    Text Solution

    |

  19. For the curve y=4x^3-2x^5, find all the points at which the tangents p...

    Text Solution

    |

  20. Minimum value of (sin^(-1)x)^(2)+(cos^(-1)x)^(2) is greater than

    Text Solution

    |

  21. If y + b = m(1)(x + a) and y + b = m(2)(x+a) are two tangents to the p...

    Text Solution

    |