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If x^2+y x^2=4 then find the xamimum val...

If `x^2+y x^2=4` then find the xamimum value of `(x^3+y^3)/(x+y)`

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The correct Answer is:
6

If `x^(2)+y^(2)=4`, …………
`x^(2)+y^(2)=4`
`x = 2 cos theta, y = 2sin theta`
`(x^(3)+y^(3))/(x+y) = x^(2)+y^(2)-xy= 4 -2 sin 2theta`
masx.value `= 4-(2)(-1)=6`
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