If (1+sec^(2)pi x). (1+sec^(2)y)= -x^(2)...

If `(1+sec^(2)pi x). (1+sec^(2)y)= -x^(2)+2x+3` then

`x= -1, y= npi, n in I`

`x = 0, y = n pi, n in I`

`x = 1, y = 2n pi, n in I`

`x = 1, y = n pi, n in I`

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The correct Answer is:

If `(1+sec^(2)pi x)` ……………
`L.H.S. = (1+sec^(2)pi x) (1+sec^(2)y)le 4`
`R.H.S. = 4- (x-1)^(2)le 4`
`:' L.H.S. = R.H.S.`
`implies (1+sec^(2)pi x) (1+sec^(2)y)= 4-(x-1)^(2)= 4`
`implies x = 1`
`:. Sec^(2)y =1`
`implies y = n pi, n in I`
`:. x =1, y = n pi, n in I`

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