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Let R be the relation defined on power s...

Let `R` be the relation defined on power set of A such that `ARB hArr n(P(A)) = n(P(B))` can be : (where `P(A)` denotes power set of `(A)`

A

Reflexive

B

Symmetric

C

Transitive

D

Equiivalence

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To solve the problem, we need to analyze the relation \( R \) defined on the power set of a set \( A \). The relation states that for sets \( A \) and \( B \), \( A R B \) if and only if \( n(P(A)) = n(P(B)) \), where \( P(A) \) and \( P(B) \) are the power sets of \( A \) and \( B \), respectively. ### Step-by-Step Solution: 1. **Understanding Power Set**: The power set \( P(X) \) of a set \( X \) is the set of all subsets of \( X \). If \( X \) has \( n \) elements, then the number of subsets (or the size of the power set) is given by \( n(P(X)) = 2^n \). 2. **Applying to Sets A and B**: For sets \( A \) and \( B \), let \( n(A) \) be the number of elements in set \( A \) and \( n(B) \) be the number of elements in set \( B \). Therefore, we can express the number of elements in their power sets as: \[ n(P(A)) = 2^{n(A)} \quad \text{and} \quad n(P(B)) = 2^{n(B)} \] 3. **Setting Up the Relation**: According to the relation \( A R B \), we have: \[ n(P(A)) = n(P(B)) \implies 2^{n(A)} = 2^{n(B)} \] 4. **Equating Exponents**: Since the bases are the same (both are 2), we can equate the exponents: \[ n(A) = n(B) \] 5. **Reflexivity**: To check if \( R \) is reflexive, we need to see if \( A R A \) holds: \[ n(P(A)) = n(P(A)) \quad \text{(True)} \] Therefore, \( R \) is reflexive. 6. **Symmetry**: To check if \( R \) is symmetric, assume \( A R B \) holds, which means \( n(A) = n(B) \). Then it follows that: \[ n(B) = n(A) \implies B R A \] Hence, \( R \) is symmetric. 7. **Transitivity**: To check if \( R \) is transitive, assume \( A R B \) and \( B R C \): \[ n(A) = n(B) \quad \text{and} \quad n(B) = n(C) \] From this, it follows that: \[ n(A) = n(C) \implies A R C \] Thus, \( R \) is transitive. 8. **Conclusion**: Since \( R \) is reflexive, symmetric, and transitive, we conclude that \( R \) is an equivalence relation on the power set of \( A \).

To solve the problem, we need to analyze the relation \( R \) defined on the power set of a set \( A \). The relation states that for sets \( A \) and \( B \), \( A R B \) if and only if \( n(P(A)) = n(P(B)) \), where \( P(A) \) and \( P(B) \) are the power sets of \( A \) and \( B \), respectively. ### Step-by-Step Solution: 1. **Understanding Power Set**: The power set \( P(X) \) of a set \( X \) is the set of all subsets of \( X \). If \( X \) has \( n \) elements, then the number of subsets (or the size of the power set) is given by \( n(P(X)) = 2^n \). 2. **Applying to Sets A and B**: ...
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