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Number of four digit number between 7000...

Number of four digit number between `7000` and `8000`, such that the thousands digit is equal to the sum of other three digit, is

A

`36`

B

`38`

C

`15`

D

`18`

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The correct Answer is:
To solve the problem of finding the number of four-digit numbers between 7000 and 8000 such that the thousands digit equals the sum of the other three digits, we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Range**: - The four-digit numbers between 7000 and 8000 have their thousands digit fixed as 7. - Therefore, we can represent any number in this range as \( 7xyz \), where \( x, y, z \) are the digits in the hundreds, tens, and units places respectively. 2. **Set Up the Equation**: - According to the problem, the thousands digit (which is 7) must equal the sum of the other three digits. - This gives us the equation: \[ x + y + z = 7 \] 3. **Determine the Constraints**: - The digits \( x, y, z \) can take values from 0 to 9. However, since we are summing to 7, they will naturally be constrained to non-negative integers. 4. **Use the Stars and Bars Method**: - To find the number of non-negative integer solutions to the equation \( x + y + z = 7 \), we can use the "stars and bars" combinatorial method. - The formula for the number of solutions in non-negative integers to the equation \( x_1 + x_2 + ... + x_r = n \) is given by: \[ \binom{n + r - 1}{r - 1} \] - Here, \( n = 7 \) (the total sum) and \( r = 3 \) (the number of variables: \( x, y, z \)). 5. **Calculate the Combinations**: - Plugging in the values into the formula: \[ \binom{7 + 3 - 1}{3 - 1} = \binom{9}{2} \] - Now, calculate \( \binom{9}{2} \): \[ \binom{9}{2} = \frac{9!}{2!(9-2)!} = \frac{9 \times 8}{2 \times 1} = \frac{72}{2} = 36 \] 6. **Conclusion**: - Therefore, the number of four-digit numbers between 7000 and 8000 such that the thousands digit equals the sum of the other three digits is **36**. ### Final Answer: The number of four-digit numbers between 7000 and 8000 such that the thousands digit is equal to the sum of the other three digits is **36**.

To solve the problem of finding the number of four-digit numbers between 7000 and 8000 such that the thousands digit equals the sum of the other three digits, we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Range**: - The four-digit numbers between 7000 and 8000 have their thousands digit fixed as 7. - Therefore, we can represent any number in this range as \( 7xyz \), where \( x, y, z \) are the digits in the hundreds, tens, and units places respectively. ...
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