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A ray of light travels along a line y=4 ...

A ray of light travels along a line `y=4` and strikes the surface of curves `y^2=4(x+y)dot` Then the equations of the line along which of reflected ray travels is `x=0` (b) `x=2` (c) `x+y` (d) `2x+y=4`

A

`x=0`

B

`x=2`

C

`x+y=4`

D

`2x+y=4`

Text Solution

Verified by Experts

The correct Answer is:
A
A ray of light …………
Focus `(0, 2)`. The point of intersection of curve and `y = 4` is `(0,4)`. From the reflection property of reflected ray passes through focus.
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