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A particle moves along a straight line s...

A particle moves along a straight line such that its displacement at any time t is given by `s = (t^(3)-6t^(2)+3t +4)m`
The velocity when the acceleration is zero, is

A

`3ms^(-1)`

B

`-12ms^(-1)`

C

`42ms^(-1)`

D

`-9ms^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
D
`v=(dx)/(dt)=3t^(2)-12t+3,a=(dv)/(dt)=6t-12=0`
`rArrt=2s`
`v_(t=2)=3xx4-12xx2+3=-9m//s`
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