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The area of region between y=sinx and x-...

The area of region between `y=sinx` and `x-` axis in the interval `[0,(pi)/(2)]` will be `:`

A

1

B

0

C

2

D

`(1)/(2)`

Text Solution

Verified by Experts

The correct Answer is:
A
`underset(0)overset(pi//2)intsinxdx=[-cosx]_(0)^(pi//2)=1`
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