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The velocity of a particle moving on the...

The velocity of a particle moving on the `x-` axis is gienv by `v=x^(2)+x(` for `xgt0)` where `v` is in `m//s` and `x` is in `m`. Find its acceleration in `m//s^(2)` when passing through the point `x=2m`

A

0

B

5

C

11

D

30

Text Solution

Verified by Experts

The correct Answer is:
D
`V=x^(2)+x`
`a=V(dv)/(dx)=(x^(2)+x)(2x+1)`
`At x=2m`
`a=(4+2)(4+1)`
`a=30m//s^(2)`
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