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Initially car A is 10.5 m ahead of car B...

Initially car `A` is `10.5 m` ahead of car `B`. Both start moving at time `t = 0` in the same direction along a straight line. The velocity-time graph of two cars is shown in figure. The time when the car `B` will catch the car `A`, will be.

A

`t=21sec`

B

`t-2sqrt(50sec`

C

`20 sec`

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
A
`x_(A)=x_(B)`
`10.5+10t=(1)/(2)at^(2)a=tan45^(@)=1`
`t^(2)-20t-21=0, t=(20+-sqrt(400+84))/(2)t=21 sec.`
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