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When two particles A and B are at point ...

When two particles A and B are at point O, A is moving with a constant velocity 50 m/s , while B is not moving. But B possesses a constant acceleration of 10 m/`s^(2)` . After how much time they will be at a distance of 125 m ?

A

`5 sec`

B

`5(1+sqrt(2))sec.`

C

`10 sec.`

D

`10(sqrt(2)+1)sec.`

Text Solution

Verified by Experts

The correct Answer is:
A, B
`S_(1)=S_(2)=125m, if S_(2)gtS_(2)then`
`50t-(1)/(2)xx10t^(2)=125`
`10t-t^(2)=25`
`t^(2)-10t+25=0`
`t=5sec`.
`S_(2)-S_(1)=125mif S_(2)gtS_(2)then,`
` (1)/(2)xx10t^(2)-50t=125`
`t^(2)-10t-25=0`
`t=(10+sqrt(100+100))/(2)`
`t=5(1+sqrt(2))sec.`
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