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A current I amperes flows through a loop...

A current `I` amperes flows through a loop abcdefgha along the edge of cube of width `l` metres as shown in figure. One corner 'a' of the loop lies at origin.

Now if a uniform external magnetic field is `vec(B) = B_(e) hat(j)` is switched on, then the unit vector in the direction of torque due to external magnetic field `(vec(B))` acting on the current carrying loop (abcdefgha)` is

A

`hat(k)`

B

`- hat(i)`

C

`(2 hat(i)-hat(j))/(sqrt(5))`

D

none of these

Text Solution

Verified by Experts

The correct Answer is:
D
`[ "Moderate"]` The current path abcdefgna can be treated as superposition of three loops fghaf, fabef and ebcde each carrying current I. The dipole moment two square loops fabef. Now the dipole moment of loop is negative y-direction and direction of external magnetic field is in positive y-direction. Therefore torque on loop is zero.
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