Consider the following statements `:`
Statement `:1 HBr` is a stronger acid than `HI` because of hydrogen bonding.
Statement `:2 F^(-)` ion has higher hydration energy than `Cl^(-)`
Statement `:3 O_(2)` is more powerful oxidising agent than `F_(2)` becuase it contains three `'O'`.
Statement `:4 ` fluorine does not form polyhalides.
and arrange in the order of true `//` false.

Options

A. `T T T F`
B. `F T F T `
C. `T F T F`
D. `F F T T `

Explanation

To analyze the given statements and determine their truth values, we will evaluate each statement one by one.

### Step 1: Evaluate Statement 1
**Statement 1:** HBr is a stronger acid than HI because of hydrogen bonding.

- **Analysis:** HBr is indeed a stronger acid than HI, but the reason given (hydrogen bonding) is incorrect. Hydrogen bonding occurs primarily with highly electronegative atoms like F, O, and N. In this case, HBr and HI do not involve such bonding. The strength of HBr as an acid compared to HI is due to the bond strength; H-I bond is weaker than H-Br bond, allowing HBr to dissociate more easily in solution.
- **Conclusion:** **False**

### Step 2: Evaluate Statement 2
**Statement 2:** F⁻ ion has higher hydration energy than Cl⁻.

- **Analysis:** The hydration energy of an ion is inversely related to its size. F⁻ is smaller than Cl⁻, which means it can interact more strongly with water molecules, leading to higher hydration energy.
- **Conclusion:** **True**

### Step 3: Evaluate Statement 3
**Statement 3:** O₂ is a more powerful oxidizing agent than F₂ because it contains three 'O'.

- **Analysis:** This statement is incorrect. F₂ is a stronger oxidizing agent than O₂ due to the high electronegativity and small size of fluorine, which allows it to attract electrons more effectively. The number of oxygen atoms in O₂ does not contribute to its oxidizing ability in comparison to F₂.
- **Conclusion:** **False**

### Step 4: Evaluate Statement 4
**Statement 4:** Fluorine does not form polyhalides.

- **Analysis:** This statement is true. Fluorine does not form polyhalides because it lacks vacant d-orbitals necessary for bonding with additional halogen atoms. Therefore, it cannot accommodate more than one halogen atom in a stable compound.
- **Conclusion:** **True**

### Final Arrangement of Statements
Now that we have evaluated all statements, we can summarize their truth values:
1. Statement 1: **False**
2. Statement 2: **True**
3. Statement 3: **False**
4. Statement 4: **True**

Thus, the final arrangement of the statements in terms of true/false is:
**False, True, False, True (FTFT)**