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consider f:R-{0}toR defined by f(x)=1-e^...

consider `f:R-{0}toR` defined by `f(x)=1-e^((1)/(x)-1)`
Q. Which of the following is/are correct?

A

`f(x)` is an increasing function

B

`f(x)` is decreasing function

C

`f(x)` is an odd function

D

`f(x)` is neither even nor odd function

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The correct Answer is:
To solve the problem, we need to analyze the function \( f(x) = 1 - e^{\left(\frac{1}{x} - 1\right)} \) and determine which statements about it are correct. ### Step 1: Differentiate the function To check if the function is increasing or decreasing, we first need to find its derivative \( f'(x) \). \[ f'(x) = \frac{d}{dx} \left( 1 - e^{\left(\frac{1}{x} - 1\right)} \right) \] Using the chain rule, we differentiate \( e^{u} \) where \( u = \frac{1}{x} - 1 \): \[ f'(x) = -e^{\left(\frac{1}{x} - 1\right)} \cdot \frac{d}{dx}\left(\frac{1}{x} - 1\right) \] Now, we differentiate \( \frac{1}{x} \): \[ \frac{d}{dx}\left(\frac{1}{x}\right) = -\frac{1}{x^2} \] Thus, we have: \[ f'(x) = -e^{\left(\frac{1}{x} - 1\right)} \cdot \left(-\frac{1}{x^2}\right) = \frac{e^{\left(\frac{1}{x} - 1\right)}}{x^2} \] ### Step 2: Analyze the sign of the derivative Now we need to analyze \( f'(x) \): 1. The term \( e^{\left(\frac{1}{x} - 1\right)} \) is always positive for all \( x \neq 0 \). 2. The term \( x^2 \) is also always positive for all \( x \neq 0 \). Therefore, \( f'(x) > 0 \) for all \( x \neq 0 \). This means that the function \( f(x) \) is increasing for all \( x \neq 0 \). ### Step 3: Check if the function is odd or even To check if \( f(x) \) is odd or even, we need to evaluate \( f(-x) \): \[ f(-x) = 1 - e^{\left(\frac{1}{-x} - 1\right)} = 1 - e^{\left(-\frac{1}{x} - 1\right)} = 1 - \frac{1}{e} e^{-\frac{1}{x}} \] Now, we need to check if \( f(-x) = -f(x) \) or \( f(-x) = f(x) \): 1. For \( f(-x) = -f(x) \): \[ 1 - e^{\left(-\frac{1}{x} - 1\right)} \neq -\left(1 - e^{\left(\frac{1}{x} - 1\right)}\right) \] 2. For \( f(-x) = f(x) \): \[ 1 - e^{\left(-\frac{1}{x} - 1\right)} \neq 1 - e^{\left(\frac{1}{x} - 1\right)} \] Thus, \( f(x) \) is neither odd nor even. ### Conclusion From our analysis, we conclude that: - The function \( f(x) \) is increasing for all \( x \neq 0 \). - The function is neither odd nor even. ### Final Answer The correct options are: - Option 1: Correct (function is increasing) - Option 4: Correct (function is neither even nor odd)

To solve the problem, we need to analyze the function \( f(x) = 1 - e^{\left(\frac{1}{x} - 1\right)} \) and determine which statements about it are correct. ### Step 1: Differentiate the function To check if the function is increasing or decreasing, we first need to find its derivative \( f'(x) \). \[ f'(x) = \frac{d}{dx} \left( 1 - e^{\left(\frac{1}{x} - 1\right)} \right) \] ...
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