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Sixteen players `S_(1)`, `S_(2)`, `S_(3)`,…,`S_(16)` play in a tournament. Number of ways in which they can be grouped into eight pairs so that `S_(1)` and `S_(2)` are in different groups, is equal to

A

`((11)!)/(216)`

B

`((12)!)/((3!)^(4))`

C

`((12)!)/((3!)^(4)(4!))`

D

`((11)!)/((3!)^(4))`

Text Solution

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The correct Answer is:
B
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