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The number of isosceles triangles with i...

The number of isosceles triangles with integer sides if no side exeeds 2016 is

A

`(1008)^(2)` if equal sides not exceed 1008

B

`2(1008)^(2)` if equal sides exceed 1008

C

`3(1008)^(2)` if equal sides have any length not exceeding 2016

D

`(2016)^(2)` if equal sides have any length not exceeding 2016

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The correct Answer is:
To find the number of isosceles triangles with integer sides where no side exceeds 2016, we can follow these steps: ### Step 1: Understand the properties of isosceles triangles An isosceles triangle has two sides of equal length. Let's denote the lengths of the two equal sides as \( n \) and the base (the third side) as \( a \). ### Step 2: Apply the triangle inequality For any triangle with sides \( a, n, n \), the triangle inequality must hold: 1. \( n + n > a \) → \( 2n > a \) → \( a < 2n \) 2. \( n + a > n \) → \( a > 0 \) 3. \( n + a > n \) → \( a > 0 \) From the first inequality, we have \( a < 2n \). The second and third inequalities simply state that \( a \) must be positive. ### Step 3: Determine the range of \( n \) Since no side can exceed 2016, we have: - \( n \leq 2016 \) ### Step 4: Determine the range of \( a \) From the triangle inequality, we have: - \( 1 \leq a < 2n \) ### Step 5: Count the possible values of \( a \) For each integer value of \( n \), the possible values of \( a \) range from 1 to \( 2n - 1 \). Therefore, the number of possible values for \( a \) is: - \( 2n - 1 \) ### Step 6: Sum the possible values of \( a \) for all valid \( n \) Now we need to sum \( 2n - 1 \) for all integer values of \( n \) from 1 to 2016: \[ \text{Total} = \sum_{n=1}^{2016} (2n - 1) \] This can be simplified as: \[ \text{Total} = \sum_{n=1}^{2016} 2n - \sum_{n=1}^{2016} 1 \] \[ = 2 \sum_{n=1}^{2016} n - 2016 \] ### Step 7: Calculate the sum of the first 2016 integers The sum of the first \( m \) integers is given by the formula: \[ \sum_{n=1}^{m} n = \frac{m(m + 1)}{2} \] Thus, for \( m = 2016 \): \[ \sum_{n=1}^{2016} n = \frac{2016 \times 2017}{2} = 2033136 \] ### Step 8: Substitute back into the total Now substituting back: \[ \text{Total} = 2 \times 2033136 - 2016 = 4066272 - 2016 = 4064256 \] ### Conclusion The total number of isosceles triangles with integer sides where no side exceeds 2016 is **4064256**. ---

To find the number of isosceles triangles with integer sides where no side exceeds 2016, we can follow these steps: ### Step 1: Understand the properties of isosceles triangles An isosceles triangle has two sides of equal length. Let's denote the lengths of the two equal sides as \( n \) and the base (the third side) as \( a \). ### Step 2: Apply the triangle inequality For any triangle with sides \( a, n, n \), the triangle inequality must hold: 1. \( n + n > a \) → \( 2n > a \) → \( a < 2n \) ...
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