What is the oxidation number of phosphorus in `H_(4)P_(2)O_(6)` molecule ?

Explanation

To find the oxidation number of phosphorus in the molecule \( H_4P_2O_6 \), we can follow these steps:

### Step 1: Identify the oxidation states of the other elements
- The oxidation state of hydrogen (H) is \( +1 \).
- The oxidation state of oxygen (O) is \( -2 \).

### Step 2: Set up the equation for the oxidation states
Let the oxidation number of phosphorus (P) be \( x \). In the molecule \( H_4P_2O_6 \):
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