What is the oxidation number of phosphorus in `H_(4)P_(2)O_(5)` molecule ?

Explanation

To find the oxidation number of phosphorus in the molecule \( H_4P_2O_5 \), we can follow these steps:

### Step 1: Assign oxidation numbers to known elements
- Hydrogen (H) has an oxidation number of +1.
- Oxygen (O) has an oxidation number of -2.

### Step 2: Set up the equation for the oxidation number of phosphorus
Let the oxidation number of phosphorus be \( x \). Since there are 2 phosphorus atoms in the molecule, their contribution to the oxidation number will be \( 2x \).
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