Home
Class 12
CHEMISTRY
The Oxidation number of S in (CH3)2SO is...

The Oxidation number of S in `(CH_3)_2`SO is :

Text Solution

Verified by Experts

`N-H` bond is more polar than `P-H` bond. Hence, `NH_(3)` forms hydrogen bonds with `H_(2)O` molecules and hence dissolves in it whereas `PH_(3)` does not dissolve and forms bubbles
Promotional Banner

Topper's Solved these Questions

  • P BLOCK ELEMENTS

    RESONANCE ENGLISH|Exercise Exercise 1 part 1 subjective ques|30 Videos
  • P BLOCK ELEMENTS

    RESONANCE ENGLISH|Exercise Exercise 1 part 2 objective que|48 Videos
  • P BLOCK ELEMENTS

    RESONANCE ENGLISH|Exercise Example|30 Videos
  • NUCLEAR CHEMISTRY

    RESONANCE ENGLISH|Exercise STAGE-II|1 Videos
  • P-BLOCK ELEMENT (BORON AND CARBON FAMILY)

    RESONANCE ENGLISH|Exercise PART - III : OLYMPIAD PROBLEMS (PREVIOUS YEARS) STAGE - V (INTERNATIONAL CHEMISTRY OLYMPIAD (IChO)) Problem 3|8 Videos

Similar Questions

Explore conceptually related problems

The Oxidation number of S in S_2O_8^(-2) is :

The oxidation number of carbon in CH_2O is.

The oxidation number of C in CH_(2)O is

The oxidation number of carbon in CH_(4) is

Oxidation number of N in (NH_(4))_(2)SO_(4) is

Assertion (A): O_(3) can act as an oxidising agent as wll as a reducing agent, but SO_(2) can act only as an oxidant. Reason (R ): The oxidation number of O in O_(3) is zero, and the oxidiation number of S in SO_(2) is +4 .

Assertion :- Oxidation number of carbon in CH_(2)O is zero. Reason :- CH_(2)O (formaldehyde) is a covalent compound.

The oxidation number of S in S_(8),S_(2)F_(2) , and H_(2)S , respectively, are

What is oxidation number? Mention the working rules used to calculate the oxidation number of an atom in a given species. Calculate the oxidation number of S in Na_(2)S,Na_(2)SO_(3),Na_(2)SO_(4),Na_(2)S_(2)O_(3) and Na_(2)S_(4)O_(6) .

The oxidation number of carbon in CH_(2)Cl_(2) is