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Which of the following compounds is most...

Which of the following compounds is most acidic ?

A

`CH_(3)CO_(2)H`

B

`(CH_(3))_(2)CHCO_(2)H`

C

`CH_(3)CH_(2)CO_(2)H`

D

`C Cl_(3)CO_(2)H`

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The correct Answer is:
To determine which of the given compounds is the most acidic, we need to analyze the stability of their conjugate bases. The acidic strength of a compound is directly proportional to the stability of its conjugate base; the more stable the conjugate base, the stronger the acid. ### Step-by-Step Solution: 1. **Identify the Compounds**: Let's denote the four compounds as follows: - Compound 1: CH3COOH (Acetic acid) - Compound 2: CH3C(=O)OH (Acetaldehyde) - Compound 3: CH3CH2C(=O)OH (Propanoic acid) - Compound 4: CCl3COOH (Trichloroacetic acid) 2. **Write the Conjugate Bases**: The conjugate bases of these acids can be represented as follows: - Conjugate base of Compound 1: CH3COO⁻ (Acetate ion) - Conjugate base of Compound 2: CH3C(=O)O⁻ (Acetate ion) - Conjugate base of Compound 3: CH3CH2C(=O)O⁻ (Propionate ion) - Conjugate base of Compound 4: CCl3COO⁻ (Trichloroacetate ion) 3. **Analyze Stability of Conjugate Bases**: - **Compound 1 (Acetate ion)**: The negative charge is delocalized over the two oxygen atoms, providing some stability. - **Compound 2 (Acetate ion)**: Similar to Compound 1, it has delocalization but lacks additional stabilizing factors. - **Compound 3 (Propionate ion)**: The negative charge is also delocalized, but the presence of an additional alkyl group (ethyl) can increase electron density, making it less stable. - **Compound 4 (Trichloroacetate ion)**: The presence of three electronegative chlorine atoms withdraws electron density from the conjugate base, stabilizing the negative charge significantly. 4. **Determine the Most Stable Conjugate Base**: Among the conjugate bases, the trichloroacetate ion (from Compound 4) is the most stable due to the strong electron-withdrawing effect of the three chlorine atoms. This stabilization of the negative charge makes the conjugate base more stable than the others. 5. **Conclusion**: Since the stability of the conjugate base is highest for Compound 4 (CCl3COOH), it is the most acidic among the given compounds. ### Final Answer: The most acidic compound is **CCl3COOH (Trichloroacetic acid)**. ---

To determine which of the given compounds is the most acidic, we need to analyze the stability of their conjugate bases. The acidic strength of a compound is directly proportional to the stability of its conjugate base; the more stable the conjugate base, the stronger the acid. ### Step-by-Step Solution: 1. **Identify the Compounds**: Let's denote the four compounds as follows: - Compound 1: CH3COOH (Acetic acid) - Compound 2: CH3C(=O)OH (Acetaldehyde) ...
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RESONANCE ENGLISH-ALDEHYDES, KETONES, CARBOXYLIC ACID-ORGANIC CHEMISTRY(Aldehydes , Ketones, Carboxylic acid)
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  3. Which of the following compounds is most acidic ?

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  4. The treatment of with concentrated KOH gives

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  5. Electrolysis can be used to determine atomic masses. A current of 0.44...

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  6. The compound which would yield 5- Oxo-2-methylhexanal on reductive ozo...

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  7. Which of the following on heating does not form an anhydride ?

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  8. The productP is :

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  9. {:(CH(3)COOH,H-COOCH(3),CH(3)-CONH(2),CH(3)-CH(2)-CH(2)-OH,),((I),(II)...

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  10. Dry distillation of calcium acetate gives :

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  11. Which one of the following reaction is called Rosenmund reaction ?

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  12. How many electrons with l=2 are there in an atom having atomic number ...

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  13. In order to get propane gas which of the following should be subjected...

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  14. Acetic acid reacts separately with the following alcohols. The rate ...

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  15. If the Planck's constant h=6.6×10^(-34) Js, the de Broglie wave length...

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  16. A new carbon-carbon bond formation is possible in:

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  17. Aldehydes and ketones may be distinguished by using

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  18. If the Planck's constant h=6.6×10^(-34) Js, the de Broglie wave length...

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  19. If the Planck's constant h=6.6×10^(-34) Js, the de Broglie wave length...

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  20. If the Planck's constant h=6.6×10^(-34) Js, the de Broglie wave length...

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