`CH_(3)CH_(2)CH_(2)CH_(2)CH_(2)COOHrarrCH_(2)CH_(2)CH_(2)-overset(overset(NH_(2))|)(C)H-COOH`
Which reagent can be used for the given conversion ?

Explanation

To solve the conversion of the carboxylic acid \( CH_3CH_2CH_2CH_2CH_2COOH \) to the amino acid \( CH_2CH_2CH_2- \overset{(NH_2)}{(C)}H-COOH \), we can follow these steps:

### Step 1: Identify the Reaction Type
The conversion involves the introduction of an amine group (\( NH_2 \)) into the structure of a carboxylic acid. This is typically done through a two-step process involving the formation of an alpha-halo carboxylic acid.

### Step 2: Formation of Alpha-Halo Carboxylic Acid
The first step is to convert the carboxylic acid into an alpha-halo carboxylic acid. This can be achieved using bromine (\( Br_2 \)) in the presence of red phosphorus (\( P \)). This reaction is known as the Hell-Volhard-Zelinsky (HVZ) reaction.

- **Reaction**:
\[ CH_3CH_2CH_2CH_2CH_2COOH + Br_2 \xrightarrow{P} CH_3CH_2CH_2CH_2CHBrCOOH \]

### Step 3: Reaction with Ammonia
In the second step, the alpha-halo carboxylic acid reacts with excess ammonia (\( NH_3 \)). The ammonia will replace the bromine atom, leading to the formation of the amino acid.

- **Reaction**:
\[ CH_3CH_2CH_2CH_2CHBrCOOH + NH_3 \xrightarrow{\text{heat}} CH_3CH_2CH_2CH_2CH(NH_2)COOH \]

### Step 4: Final Product
The final product after the reaction with ammonia is the desired amino acid:
\[ CH_3CH_2CH_2CH_2CH(NH_2)COOH \]

### Summary of Reagents
The reagents required for this conversion are:
1. Red Phosphorus (\( P \))
2. Bromine (\( Br_2 \))
3. Excess Ammonia (\( NH_3 \))

### Final Answer
The reagents that can be used for the given conversion are:
- Red Phosphorus and Bromine (for the HVZ reaction)
- Excess Ammonia (for substitution of bromine with \( NH_2 \))

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