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A current l flows through a closed loop ...

A current l flows through a closed loop as shown in figure .The magnetic field at the centre O is

A

`(mu_(0)i)/(2R)((2pi-theta)/(2pi))^(2)`

B

`(mu_(0)i)/(2R)((2pi-theta)/(2pi))`

C

`(mu_(0)i)/(2R)(2pi-theta)`

D

`(mu_(0)i)/(2R)(2pi-theta)^(2)`

Text Solution

Verified by Experts

The correct Answer is:
A
`B=(mu_(0)i)/(4piR)(2pi-0)`
where,`(2pi-0)R=2piR`
`R'=(2piR)/(2pi-0) rArr B=(mu_(0)i)/(2R)((2pi-theta)/(2pi))^(2)`
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