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Figure shows an amperian path ABCDA. Par...

Figure shows an amperian path ABCDA. Part ABC is in vertical plane PSTU while part CDA is in horizontal plane PQRS. Direction of circulation along the path is shown by ann arrow near point B and D. `oint vec(B).dvecl` for this path according to Ampere's law will be

A

`(i_(1)-i_(2)+i_(3))mu_(0)`

B

`(-i_(1)+i_(2))mu_(0)`

C

`i_(3)mu_(0)`

D

`(i_(1)+i_(2))mu_(0)`

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The correct Answer is:
D
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RESONANCE ENGLISH-ELECTRODYNAMICS-Exercise-1 PART-2
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