For boron family (B,Al,Ga,In and Tl)
x : Number of elements which are solid at `40^(@)`
`y` : period number of element which has greater ionization energy than element just above and below it in periodic table.
` Z`: Period number of most abundant element of group `13`.
Report your answer `x+2y+3z`

Explanation

To solve the problem step by step, let's break down each part of the question regarding the boron family (B, Al, Ga, In, Tl):

### Step 1: Determine x
**x** is defined as the number of elements in the boron family that are solid at 40°C.

- The elements in the boron family are:
- Boron (B)
- Aluminum (Al)
- Gallium (Ga)
- Indium (In)
- Thallium (Tl)

- At 40°C:
- Boron is a solid.
- Aluminum is a solid.
- Gallium is a solid at room temperature but melts at around 30°C, so it is not solid at 40°C.
- Indium is a solid.
- Thallium is a solid.

Thus, the solid elements at 40°C are B, Al, In, and Tl. Therefore, **x = 4**.

### Step 2: Determine y
**y** is defined as the period number of the element that has greater ionization energy than the element just above and below it in the periodic table.

- In the boron family:
- Boron (B) is in period 2.
- Aluminum (Al) is in period 3.
- Gallium (Ga) is in period 4.
- Indium (In) is in period 5.
- Thallium (Tl) is in period 6.

- We need to check the ionization energies:
- Boron has a higher ionization energy than Aluminum (B > Al).
- Aluminum has a lower ionization energy than Gallium (Al < Ga).
- Gallium has a higher ionization energy than Indium (Ga > In).
- Indium has a lower ionization energy than Thallium (In < Tl).

The element with greater ionization energy than both its neighbors is Gallium (Ga) in period 4. Thus, **y = 4**.

### Step 3: Determine z
**z** is defined as the period number of the most abundant element in group 13.

- The most abundant element in group 13 is Aluminum (Al), which is in period 3. Therefore, **z = 3**.

### Step 4: Calculate the final result
Now, we can report the answer in the form of \( x + 2y + 3z \).

- Substitute the values:
- \( x = 4 \)
- \( y = 4 \)
- \( z = 3 \)

Now, calculate:
\[ x + 2y + 3z = 4 + 2(4) + 3(3) \]
\[ = 4 + 8 + 9 \]
\[ = 21 \]

### Final Answer
The final answer is **21**.

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