Reduction of `117.5 g BCl_(3)` by `H_(2)` in silent electric discharge produces `HCl`, which required `500 mL` of `xM NaOH` for neutralization. Report `x`.

Explanation

To solve the problem step by step, let's break down the information provided and perform the necessary calculations.

### Step 1: Calculate the number of moles of BCl₃
The number of moles can be calculated using the formula:

\[ \text{Number of moles} = \frac{\text{Weight}}{\text{Molecular Weight}} \]
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