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Straight chain polymer is formed by hydr...

Straight chain polymer is formed by hydrolysis of `[x]` which is tetrasubstituted chloromethylsilane then followed by condensation polymerization. Atomicity of `[x]` is:

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To solve the problem, we need to determine the atomicity of the compound `[x]`, which is a tetrasubstituted chloromethylsilane. Here’s a step-by-step breakdown of the solution: ### Step 1: Identify the Structure of `[x]` - The compound `[x]` is described as a tetrasubstituted chloromethylsilane. This means it has a silicon (Si) atom bonded to four substituents, which include chloromethyl (–CH2Cl) and methyl (–CH3) groups. - A common structure for such a compound is Si(CH3)4, which means silicon is bonded to four methyl groups, but since it is tetrasubstituted with chloromethyl, we can assume a structure like Si(CH3)3(CH2Cl). ### Step 2: Write the Molecular Formula - The molecular formula for `[x]` can be derived from its structure. - For Si(CH3)3(CH2Cl), we have: - 1 Silicon (Si) - 3 Methyl groups (CH3) contribute 3 Carbon (C) and 9 Hydrogen (H) - 1 Chloromethyl group (CH2Cl) contributes 1 Carbon (C), 2 Hydrogen (H), and 1 Chlorine (Cl) - Thus, the total components are: - Silicon (Si): 1 - Carbon (C): 3 (from CH3) + 1 (from CH2Cl) = 4 - Hydrogen (H): 9 (from CH3) + 2 (from CH2Cl) = 11 - Chlorine (Cl): 1 ### Step 3: Calculate the Atomicity - Atomicity is the total number of atoms in the molecule. - From the components we identified: - Silicon (Si): 1 - Carbon (C): 4 - Hydrogen (H): 11 - Chlorine (Cl): 1 - Now, we can sum these up: - Total Atomicity = 1 (Si) + 4 (C) + 11 (H) + 1 (Cl) = 17 ### Conclusion - Therefore, the atomicity of the compound `[x]` is **17**.
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