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A straight wire with a resistance of r p...

A straight wire with a resistance of `r` per unit length is bent to form an angle `2alpha`.A rod of the same wire perpendicular to the angle bisector (of `2alpha`) forms a closed triangular loop.This loop is placed in a uniform magnetic field of induction `B`.Calculate the current in the wires when the rod moves at a costant speed `V`.

Text Solution

Verified by Experts

The correct Answer is:
A, B
`epsilon=BV l,i=epsilon/R=(BVl)/[r[l+(2x)/(cos alpha)]]` where `cot alpha=x/(l+2)`
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