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Initially the 900muF capacitor is charge...

Initially the `900muF` capacitor is charged to 100 V and the `100muF` capacitor is uncharged in the figure shown. Then the switch `S_(2)` is closed for a time `t_(1)`, after which it is opened and at the same instant switch `S_(1)` is closed for a time `t_(2)` and then opened. It is now found that the `100muF` capacitor is charged to 300 V. If `t_(1) and t_(2)` minimum possible values of the time intervals, then findout `(t_(1))/(t_(2))`

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