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How are XeO(3) and XeOF(4) prepared?...

How are `XeO_(3)` and `XeOF_(4)` prepared?

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The correct Answer is:
Hydrolysis of `XeF_(4)` and `XeF_(6)` with water gives `XeO_(3)`
`6XeF_(4)+12H_(2)Oto4Xe+2XeO_(3)+24HF+3O_(2)`
`XeF_(6)+3H_(2)OtoXeO_(3) + 6 HF`
On other hand, partial hydrolysis of XeF_(6)` gives `XeOF_(4)`
`XeF_(6)+H_(2)O to XeOF_(4) + 2 HF`
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Statement-1 : Hydrolysis of XeF_(6) represents a redox reaction. Statement-2 : The products of hydrolysis are XeOF_(4) and XeO_(3) where the oxidation states of all elements remain the same as it was in the reacting state.

If the central atom is of third row or below this in the periodic table, then lone pair will occupy a stereochemically inactive s-orbital and bonding will be through almost pure p-orbitals and bond angles are nearly 90^(@) , if the substituent's electronegativity value is le 2.5 . The hybridisation of atomic orbitals of central atom "Xe" in XeO_(4), XeO_(2)F_(2) and XeOF_(4) respectively.

If the central atom is of third row or below this in the periodic table, then lone pair will occupy a stereochemically inactive s-orbital and bonding will be through almost pure p-orbitals and bond angles are nearly 90^(@) , if the substituent's electronegativity value is le 2.5 . The hybridisation of atomic orbitals of central atom "Xe" in XeO_(4), XeO_(2)F_(2) and XeOF_(4) respectively.

(a) Write the balanced chemical equations for obtaining XeO_(3) " and " XeOF_(4) "from "XeF_(6). (b) Account for the followingk : (i) H_(2)S is less acidic then H_(2) Te. (ii) H_(3)PO_(2) has reducing nature. (iii) SO_(2) is an air pollutant.

Assertion (A): Sodium perxenate (Na_(4)XeO_(6)) reacts with NaF in acidic medium to give XeO_(3) and F_(2) Reason (R ): XeO_(6)^(4-) is a stronger oxidant than F_(2) .

Number of lone pairs (s) in XeOF_(4) is/are

Molecular shape of ClF_(3) , l_(3)^(-) and XeO_(3) respectively are

Predict the shape of the following Xenon compounds (a) XeO_(3) (b) XeOF_(4) (c ) XeO_(2)F_(2) .

Shape of XeOF_(4) is

In case of XeO_(2) F_(2) and XeF_(6) , Xe is with

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