In a laboratory, liquid in a thermally insulated container is stirred for one, `hr`, by a mechanical linkage to a in surrounding, for this process:

Options

A. `W lt 0 , q=0`
B. `W lt 0 , q gt 0`
C. `W lt 0 , q gt 0`
D. `W gt 0 , q=0`

Explanation

To solve the problem, we need to analyze the situation described in the question. We have a liquid in a thermally insulated container that is being stirred for one hour. Let's break down the components of this scenario step by step.

### Step-by-Step Solution:

1. **Understanding the System**:
- We have a liquid in a thermally insulated container. This means that no heat can enter or leave the system (the container) during the stirring process.

2. **Identifying Heat Transfer (q)**:
- Since the container is thermally insulated, there is no heat transfer between the system and the surroundings. Therefore, we can conclude that:
\[ q = 0 \]

3. **Identifying Work Done (W)**:
- Stirring the liquid involves applying a force to move the liquid, which constitutes work done on the system. Since work is being done to stir the liquid, this work is positive. Therefore, we can conclude that:
\[ W > 0 \]

4. **Combining the Results**:
- From our analysis, we have determined that:
- Work done on the system (W) is greater than zero.
- Heat transfer (q) is equal to zero.

5. **Choosing the Correct Option**:
- Now, we can look at the options provided in the question:
- **Option A**: Work < 0, q = 0
- **Option B**: Work < 0, q > 0
- **Option C**: Work < 0, q > 0
- **Option D**: Work > 0, q = 0
- The only option that matches our findings (W > 0 and q = 0) is:
\[ \text{Option D: Work > 0, q = 0} \]

### Final Answer:
The correct answer is **Option D: Work > 0, q = 0**.

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