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The specific heats of iodine vapour and ...

The specific heats of iodine vapour and solid are 0.031 and 0.055 cal/g respectively. If heats of sublimation of iodine is 24 cal/g at `200^(@)C`, what is its value at `250^(@)C` ?

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The correct Answer is:
`22.8 cal//g`
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The specific heats of iodine vapour and solid are 0.031 and 0.055 cal//g respectively. If heat of sublimation of iodinde is 24cal//g at 200^(@)C , what is its value at 250^(@)C ?

Chemical reactions are invariably associated with the transfer of energy either in the form of hear or light. In the laboratory, heat changes in physical and chemical processes are measured with an instrument called calorimeter. Heat change in the process is calculated as: q= ms Delta T , s= Specific heat = c Delta T = Heat capacity. Heat of reaction at constant pressure is measured using simple or water calorimeter. Q_(v)= Delta U = Internal energy change, Q_(P) = DeltaH, Q_(P) = Q_(V) + P Delta V and DeltaH = Delta U+ Delta nRT . The amount of energy released during a chemical change depends on the physical state of reactants and products, the condition of pressure, temperature and volume at which the reaction is carried out. The variation of heat of reaction with temperature and pressure is given by Kirchoff's equation: (DeltaH_(2) - DeltaH_(1))/(T_(2)-T_(1))= Delta C_(P) (At constant pressure), (DeltaU_(2) - DeltaU_(1))/(T_(2)-T_(1)) = DeltaC_(V) (At constant volume) The specific heat of I_(2) in vapoour and solid state are 0.031 and 0.055 cal/g respectively. The heat of sublimation of iodine at 200^(@)C is 6.096 kcal mol^(-1) . The heat of sublimation of iodine at 250^(0)C will be

The molar heat capacities of Iodine vapour and solid are 7.8 and 14 cal/mol respectively. If enthalpy of iodine is 6096 cal/mol at 200^(@)C , then what is DeltaU (internal energy change) at 250^(@)C in cal/mol

Enthalpy of sublimation of iodine is "24 cal g"^(-1)" at " 200^(@)C . If specific heat of l_(2)(s) and l_(2) (vap) are 0.055 and 0.031 respectively, then enthalpy of sublimation of iodine at 250^(@)C in "cal g"^(-1) is:

Enthalpy of sublimation of iodine is "24 cal g"^(-1)" at " 200^(@)C . If specific heat of l_(2)(s) and l_(2) (vap) are 0.055 and 0.031 respectively, then enthalpy of sublimation of iodine at 250^(@)C in "cal g"^(-1) is:

The mass, specific heat capacity and the temperature of a solid are 1000g,(1/2) ((cal)/g) and 80 degrees C respectively. The mass of the liquid and the calorimeter are 900g and 200g. Initially, both are at room temperature 20 degrees C. Both calorimeter and the solid are made of the same material. In the steady state, temperature of mixture is 40 degrees C, then specific heat capacity of the unknown liquid is;

The mass, specific heat capacity and the temperature of a solid are 1000g,(1)/(2) (cal)/g ^(@)C and 80^(@)C respectively. The mass of the liquid and the calorimeter are 900g and 200g . Initially,both are at room temperature 20^(@)C Both calorimeter and the solid are made of same material. In the steady state, temperature of mixture is 40^(@)C , then specific heat capacity of the unknown liquid.

Steam at 100°C is passed into 100 g of ice at 0°C . Finally when 80g ice melts the mass of water present will be [Latent heat of fusion and vaporazisation are 80 cal g^(-1) and 540 cal g^(-1) respectively, specific heat of water = 1 cal g^(-1) °C^(-1) ]

10 gram of water at 45^(@)C is added to 5 gram of ice at -30^(@)C . Find the final temperature of the mixture. Specific heat of ice is 0.55 cal g^(-1)""^(@)C^(-1) and that of water is 1.0 cal g^(-1)""^(@)C^(-1) latent heat of fusion of ice is 80 cal g^(-1) ? (ii) To rise the temperature of 100 gram of water from 24^(@) to 90^(@)C by steam at 100^(@)C . Calculate the amount of steam required. Specific heat of water is 1.0 cal g^(-1)""^(@)C^(-1) . Latent heat of steam is 540 Cal kg^(-1) .

The thermal capacity of 100 g of aluminum (specific heat = 0.2 cal//g^(@)C ) is

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