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Calculate the lattice energy of the reac...

Calculate the lattice energy of the reaction
`Li^(o+)(g) +CI^(Theta) (g) rarr LiCI(s)`
from the following data:
`Delta_("sub")H^(Theta)(Li) = 160.67 kJ mol^(-1), (1)/(2)D(CI_(2)) = 122.17 kJ mol^(-1)
IP(Li) = 520.07 kJ mol^(-1),E_(A)(CI) = - 365.26 kJ mol^(-1)` and `Delta_(f)H^(Theta)(LiCI) =- 401.66 kJ mol^(-1)`

A

-837

B

-959

C

-1567

D

-37

Text Solution

Verified by Experts

The correct Answer is:
A
`DeltaH_(f)^(@)(LICI)= -q=DeltaH_("sub")(Li)+1//2 Delta_("diss")(Cl_(2))+Delta H_(lp)(Li)+DeltaH_(EA)(Cl)+DeltaH_(L.E)`
`-400=160+(244)/(2)+520-365+Delta H_(L.E)`
`Delta H_(L.E)= -400-437= -837 kJ "mole"^(-1)`
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