Home
Class 12
CHEMISTRY
Explain why heat of neutralisation of st...

Explain why heat of neutralisation of strong acid and strong base is constant irrespective of nature of strong acid or the strong base.

A

salt formed does not hydrolysis

B

only `H^(+)` and `OH^(-)` ions react

C

The strong base and strong acid react completely

D

The strong base and strong acid react in aqueous solution

Text Solution

Verified by Experts

The correct Answer is:
B
In neutralization of strong acid and base only `H^(+)` and `OH^(-)` ions react in every case. So, heat of neutralization is remain constant and equal to `-13.7 kcal` (approximate).
Promotional Banner

Topper's Solved these Questions

  • THERMODYNAMICS

    RESONANCE ENGLISH|Exercise Exercise -2 Part-I: Only one option correct type|23 Videos

  • THERMODYNAMICS

    RESONANCE ENGLISH|Exercise Exercise-2 II: Single and double value integer type|16 Videos

  • THERMODYNAMICS

    RESONANCE ENGLISH|Exercise H-1|1 Videos

  • TEST SERIES

    RESONANCE ENGLISH|Exercise CHEMISTRY|50 Videos

Similar Questions

Explore conceptually related problems

Why is heat of neutralisation for a strong acid and strong base constant ?

The heat of neutralization for a strong acid by a strong base is a constant

The heat of neutralization of a strong acid by a strong base is a constant because :

Heat of neutralization of strong acid against strong base is constant and is equal to

Explain why heat of neutralisation of strong acid and weak base is less than 57.1 kJ .

The heat of neutralisation for strong acid and strong base forming 2 moles of water is

The heat of neutralization of any strong acid and a strong base is nearly equal to :

Why is the heat of neutralization of a strong acid by a strong base is constant as 57.0 kJ/mole?

Is the process of neutralisation of a strong acid by a strong base a redox process ?

Enthalpy of neutralisation of all strong acids and strong bases has the same value because

RESONANCE ENGLISH-THERMODYNAMICS-Exercise -1 Part -II Only option correct type
  1. When a certain amount of ethylene was combusted, 5644 kJ heat was evol...

    Text Solution

    |

  2. AT 300K, the standard enthalpies of formation of C(6)H(5)COOH(s), CO(2...

    Text Solution

    |

  3. In the reaction CS(2)(l)+3O(2)(g)rarrCO(2)(g)+2SO(2)(g)DeltaH= -265 kc...

    Text Solution

    |

  4. If enthalpy of dissociation of CH(4) and C(2)H(6) are 320 and 360 calo...

    Text Solution

    |

  5. The heat of hydrogenation of ethane is x(1) and heat of benzene is x(2...

    Text Solution

    |

  6. Calculate the resonance energy of gaseous benzene from the given data ...

    Text Solution

    |

  7. Bond dissociation energies of H(2),Cl(2) and HCl((g)) are 104, 58 and ...

    Text Solution

    |

  8. AB, A(2) and B(2) are diatomic molecules. If the bond enthalpies of A...

    Text Solution

    |

  9. One mole of anhydrous MgCl(2) dissolves in water and librates 25 cal//...

    Text Solution

    |

  10. Born-Haber cycle can be used to estimate:

    Text Solution

    |

  11. The enthalpy of solution of NaOH(s) in water is -41.6 kJ//"mole" When ...

    Text Solution

    |

  12. The enthalpy change for the reaction of 5 litre of ethylene with 5 lit...

    Text Solution

    |

  13. For which one of the follwing reactions, molar enthalpy change of a re...

    Text Solution

    |

  14. Calculate the lattice energy of the reaction Li^(o+)(g) +CI^(Theta) ...

    Text Solution

    |

  15. The enthalpy of neutralization of which of the following acid & base i...

    Text Solution

    |

  16. Explain why heat of neutralisation of strong acid and strong base is c...

    Text Solution

    |

  17. Equal volumes of methanoic acid and sodium hydroxide are mixed. If x i...

    Text Solution

    |

  18. If CH(2)COOH+OH^(-)rarrCH(3)COO^(-)+H(2)O+q(1) H^(+)+OH^(-)rarrH(2)O...

    Text Solution

    |

  19. If heat of dissocitation of CHCl(2)COOH is 0.7 kcal/mole then Delta H ...

    Text Solution

    |

  20. Enthalpy of neutralization of H(3)PO(3) acid is -106.68kJ//mol using N...

    Text Solution

    |