Home
Class 12
CHEMISTRY
STATEMENT-1: when 2 faraday of charge is...

STATEMENT-1: when 2 faraday of charge is passed through 0.1 M `H_2SO_4` (aq) ,11.2 litre `O_2` evolved at STP.
STATEMENT-2: Molecular mass of oxygen is 32

Text Solution

Verified by Experts

Mole of `O_(2)xx4=2(H_(2)OtoO_92)+4H^(+)+4e^(-))`
Mole of `O_(2)=0.5`
volume of `O_(2)` at `S.T.P=11.2Lt`.
Promotional Banner

Topper's Solved these Questions

  • ELECTROCHEMISRY

    RESONANCE ENGLISH|Exercise Subjective Questions|14 Videos

  • ELECTROCHEMISRY

    RESONANCE ENGLISH|Exercise Objective Questions|41 Videos

  • ELECTROCHEMISRY

    RESONANCE ENGLISH|Exercise Exercise|112 Videos

  • ELECTRO CHEMISTRY

    RESONANCE ENGLISH|Exercise PHYSICAL CHEMITRY (ELECTROCHEMISTRY)|53 Videos

  • EQUIVALENT CONCEPT & TITRATIONS

    RESONANCE ENGLISH|Exercise Part -IV|22 Videos

Similar Questions

Explore conceptually related problems

Molecular mass of H_(2)O_(2) is

STATEMENT-1: Gram molecular mass of O_(2) is 32. STATEMENT-2: Relative atomic mass of oxygen is 32 a.m.u.

When SO_2 is passed through a solution of H_2 S in water :

STATEMENT-1: Faraday is the charge that liberates 1 eq. of metal at cathode. and STATEMENT-2: Passage of 1 Faraday charge through aq. MgCl_(2) liberates 12g Mg at cathode.

The mass of 11.2 litre of a certain gas at S.T.P. is 24 g. Find the gram molecular mass of the gas.

STATEMENT -1 : In 32 g of O_(2) , two gram of oxygen atom are present. and STATEMENT -2 : Molecular weight of O_(2) will be 32 g.

For preparing 0.1 M solution of H_(2)SO_(4) in one litre, we need H_(2)SO_(4)

Find the equation of a circle passing through (1,1),(2,-1) and (3,2)

Volume of gases evolved when dill. H_(2)SO_(4) is electrolysed using 2F at STP

STATEMENT-1: For the reaction NaOH + H_(2)CO_(3) to NaHCO_(3) + H_(2)O equivalent weight of H_(2)CO_(3) is 62. STATEMENT-2: n factor of H_(2)CO_(3) is 1 (in above reaction) and equivalent mass =("Molecular mass")/("n factor")